Skip to main content

Seahawks Own No. 18 Overall Pick In 2018 NFL Draft

It's Seattle's highest pick since 2012 when the team took Bruce Irvin at No. 15 overall.

The League's 83rd annual draft process will take place April 26-28 at AT&T Stadium in Arlington, Texas, and following Sunday's slate of NFL action, picks 1-20 are now set. 

The Seahawks, who finished the 2017 regular season with a record of 9-7, will pick No. 18 overall, the team's highest draft pick since 2012 when Seattle selected defensive end Bruce Irvin at No. 15 overall after trading back from the 12th pick.

Seattle has selected No. 18 overall just twice in franchise history, taking defensive tackle Manu Tuiasosopo at the spot in 1979 and linebacker Tony Woods with the pick in 1987. 

In recent seasons, the No. 18 overall pick has yielded players like former University of Washington Husky Marcus Peters, who went to the Kansas City Chiefs in 2015; Alabama center Ryan Kelly, who went No. 18 overall to the Indianapolis Colts in 2016; and USC cornerback Adoree' Jackson, who last year went to the Tennessee Titans with the 18th pick. 

The draft order is determined by overall record, and with four other teams finishing the 2017 regular season with the same mark as the Seahawks, strength of schedule is used as the official tiebreaker. 

Fan photos from the Seahawks' Week 17 game against the Arizona Cardinals.

This article has been reproduced in a new format and may be missing content or contain faulty links. Please use the Contact Us link in our site footer to report an issue.